the function f(x)=( x^2-6x-7)/(x+1)?

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the function f(x)=( x^2-6x-7)/(x+1)?

2007-09-25 14:49:13 · 3 answers · asked by nala 1 in Science & Mathematics ➔ Mathematics

3 answers

the guys above me are correct but they did not take care of domain and range
the domain of the function should be mentioned
x cannot be -1 as if it is -1 denominator is 0
so domain is R-{0}
range is R-{-7}
hope it is clear

2007-09-25 14:59:40 · answer #1 · answered by shuaib 2 · 0⤊ 0⤋

f(x)=( x^2-6x-7)/(x+1)
Factor ( x^2-6x-7)
= (x -7) (x + 1)
Now divide by x=1
f(x)= x -7

2007-09-25 21:52:14 · answer #2 · answered by ignoramus 7 · 0⤊ 0⤋

The numerator is factorable:
(x-7)(x+1)/x+1
f(x)=x-7

2007-09-25 21:55:28 · answer #3 · answered by jim m 5 · 0⤊ 0⤋