if you had 12 marbles 6 were red 6 were green what is the greatest number of marbles you would have to take out of the box in order to make sure that you had two marbles of the same color and two marbles of different colors without looking of course. Can u plz explain how you got the answer
2007-09-25 14:34:20 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Two same color AND Two different color is 7.
2007-09-25 14:43:14 · answer #1 · answered by ideaquest 7 · 0⤊ 0⤋
Seven. Assuming that by some chance you drew out 6 in a row that were all the same color, the 7th marble would have to be the other color. Any few and you may not have 2 of a different color.
2007-09-25 21:37:08 · answer #2 · answered by charonnisis 3 · 0⤊ 0⤋
It would be possible if you picked six marbles that by weird luck you got all 6 red (or all 6 green) so you'd need to pick 7 to be absolutely sure you had two marbles of different colors. To be sure of two of the same you'd only need to pick 3 because even if the first two were different, the third would have to match one of them.
2007-09-25 21:38:20 · answer #3 · answered by hayharbr 7 · 0⤊ 0⤋
7
if you drew 6, or less, you may draw all the same color,, at 7 you can be sure that there will be marbles of both colors, because there are only 6 of each color
2007-09-25 21:39:38 · answer #4 · answered by jr 1 · 0⤊ 0⤋
you would have to take out 8 marbles to have 4 left.
2007-09-25 21:38:37 · answer #5 · answered by your friend 2 · 0⤊ 0⤋
The initial chances are 50/50% for each colour.
You'd have to take one more than half to be certain.
So the answer in both cases is 7.
2007-09-25 21:39:40 · answer #6 · answered by Robert S 7 · 0⤊ 0⤋
9764.12
2007-09-25 21:37:34 · answer #7 · answered by Anonymous · 0⤊ 0⤋