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c=13,a=12

a=4,b=4square root of 3

a=4,c=8

2007-09-25 13:19:49 · 1 answers · asked by edwina 1 in Science & Mathematics Mathematics

1 answers

a² + b² = c²

Plug in the values you are given and get the unknown value

PROBLEM 1:
c = 13, a = 12

Square them:
c² = 169, a² = 144

Plug them into a² + b² = c²
144 + b² = 169

Solve for b²
b² = 169 - 144
b² = 25

Take sqrt of both sides:
b = sqrt(25)
b = 5


PROBLEM 2:
a = 4, b = 4 sqrt(3)

Square them:
a² = 16, b² = 4 x 4 x 3 = 48

Plug them into a² + b² = c²
16 + 48 = c²

Solve for c²
c² = 64

Take sqrt of both sides
c = 8


PROBLEM 3:
a = 4, c = 8

Square them:
a² = 16, c² = 64

Plug them into a² + b² = c²
16 + b² = 64

Solve for b²
b² = 64 - 16
b² = 48

Take sqrt of both sides:
b = sqrt(48)
b = sqrt(16 * 3)
b = sqrt(16) * sqrt(3)
b = 4 sqrt(3)

2007-09-25 13:24:24 · answer #1 · answered by Puzzling 7 · 0 0

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