plz help me i need it asap?

Question

Let delta-f1 = 1; delta-f2 = 3; delta-f3 = 5 ...
a.What is the pattern for the delta-f sequence? (Use words, de-
scribe)
b. What is a formula for the delta-f sequence? (don't use a recursive formula)
c. Find the sequence f that gives the delta-f sequence as it's
differences. Start with f1 = 1
d. Draw a conclusion.

I cant understand part c and d
to part b i have the answer 2n-1
where n is the term number as delta-f is an arithmetic progression.
Can someone plz help me with part c and d

Answer 1

ironduke8159 has given the best explanation. But I believe the next term is 9. I'm thinking of the following sequence:

f(n) = (n-3)(n-2)(n-1) +2n-1

Only 3 terms may not be enough.

Answer 2

It is like the next delta is equal to the previous delta plus two hence
fn=f(n-1)+2
where n is a whole number greater than or equal to 1
and with f1=1
hence it is an artimetic progression or sequence with constant 2.

Answer 3

Each successive term is obtained by adding 2 to the previous term.

deltf-n = 2n-1

The 1st differences are all = 2
The 2nd differences are all = 0

Since the first differences all = 2 this is an arithmetic sequence with d = 2

Answer 4

Arithmetic progression 1, 3, 5, 7.....All prime #'s. Next.................

Answer 5

I don't understand your question, as your notation confuses me.

Answer 6

ok