Velocity = Distance / Time
BUT - velocites requires an overall displacement and within that - a direction.
so the variables afffected by distance and time are designated solely by its displacement and direction.
Velocity is not the same as speed, which is a linear measurement (dependant on one direction)
Velocities can have hundreds of directions ending in a displacement (like a jets flightpath)
ergo - the affect on time and distance is its DISPLACEMENT.
2007-09-25 12:02:30
·
answer #1
·
answered by gary_j_hay 3
·
0⤊
1⤋
Velocity does not change with distance and time. The only way that velocity can change is when a force is applied. On Earth, things slow down because of friction from the air resistance.
2007-09-25 18:58:37
·
answer #2
·
answered by zi_xin 5
·
0⤊
0⤋
ok to be simple if the Speed is constant then
V=d/t
getting more complicated if the speed change in time the you should use the full equation that is
x(t) = x(to) + V(t-to) +1/2 a(t-to)^2
in this case the acceleration is constant; however if you now just this Eq is simple going back to constant speed. because if the speed is constant the a (acceleration) is 0 and then we've got
x(t)=x(to) + V(t-to) => x(t)-x(to) = V (t - to) or in other words
V= dx/dt
and that's our first eq but written using differential notation.
if you ever forget how to reach the main equation.
@@@ x(t) = x(to) + V(t-to) +1/2 a(t-to)^2 @@@@@@
and you know how to integrate, you can always remember this
a = d^2 x/ (dt)^2, here you can easily through ussing integration methods reach the expression above.
2007-09-25 19:15:32
·
answer #3
·
answered by heavy84 2
·
0⤊
0⤋
depends on the medium that the object is traveling in.
in interstellar space, velocity (theoretically) will stay the same in infinite time and distance or until some outside force acts on the object. on the surface of planet earth, velocity decreases with as time and distance increased (inversely proportional).
2007-09-25 19:03:21
·
answer #4
·
answered by oldguy 6
·
0⤊
0⤋
velocity= distance/time taken
2007-09-25 18:57:44
·
answer #5
·
answered by pwincess_laroosh 2
·
0⤊
0⤋
That depends, is the object accelerating?
2007-09-25 18:58:15
·
answer #6
·
answered by Mαtt 6
·
0⤊
0⤋
= distance / time
2007-09-25 18:57:00
·
answer #7
·
answered by conejito 2
·
0⤊
0⤋