How much work and friction is done, by a 5.00-kg block that slides 2.50 down a rough 30.0 incline?

Question

starting from rest, a 5.00-kg block slides 2.50 m down a rough 30.0 degree incline. The cofficient of kinetic friction between block and incline in mk=0.436. what would the work done by the force of gravity be, the work done by the friction force between the block and incline be. and the work done by the normal force.

Answer 1

No work done by the Normal force since work is force times displacement.

The work done by gravity is
m*g*h
where h=2.5*sin(30)

friction is the normal force times uk, and the work is times the displacement
m*g*h*cos(30)*uk*2.5

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