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Spiderman steps from the top of a tall building. He falls freely from rest to the ground a distance of . He falls a distance of 4.00 in the last interval of time of 1.10 of his fall.

2007-09-25 11:22:54 · 1 answers · asked by Natiphy2007 1 in Science & Mathematics Physics

1 answers

we know from the normal laws of acceleration that the distance traveled by a free falling object is
h = (Vi + Vf) t /2
and in this case Vf = Vi + 9.8x1.1
so the distance traveled, 4.00, =
4.00 = (Vi + Vi + 9.8x1.1) 1.1 / 2
so from that you can find his speed as he passed the point just 4.00 above the ground.
and using the same eq you can find the distance traveled from rest to Vi.
add the two distances together and that's the height.

2007-09-25 11:58:43 · answer #1 · answered by Piglet O 6 · 0 0

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