...wouldn't everyone be to drunk to finish the song?
2007-09-25 10:52:42 · 21 answers · asked by Landra 5 in Entertainment & Music ➔ Polls & Surveys
Most def!
2007-09-25 10:54:54 · answer #1 · answered by Fly girl 7 · 2⤊ 0⤋
Depends on how many people you have in the room... You have 99 people in the room, only the first few will be drunk, but the time the beer gets to the last guy, there isnt much left
2007-09-25 10:59:12 · answer #2 · answered by Joe M 7 · 0⤊ 0⤋
ninety 8 bottles of beer on the wall, ninety 8 bottles of beer! you're taking one down, bypass it around, ninety seven bottles of beer on the wall.....!!! *after some hours of that and probable some drinks so we are waiting to end* a million bottle of beer on the wall, a million bottle of beer! you're taking one down, bypass it around, not extra useful bottles of beer on the wall :( we finished
2016-11-06 08:59:57 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Good point, and who keeps bottles of beer on the wall anyway? I keep mine in the fridge or a cooler.
2007-09-25 10:56:19 · answer #4 · answered by slushsledelephant 2 · 1⤊ 0⤋
Have very many people ever finished the song?
2007-09-25 10:56:54 · answer #5 · answered by zil28ennov 6 · 1⤊ 0⤋
Shlor then theylll flake a sink ddown and por it
dddddown the coorkkk
2007-09-25 11:08:40 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Yes, I think that's actually the whole point of the song.
2007-09-25 10:56:13 · answer #7 · answered by fizzygurrl1980 7 · 1⤊ 0⤋
no because I would put coke in my beer bottles! then I would be too hyper to finish it. lol
2007-09-25 10:56:16 · answer #8 · answered by Real Vampires Sparkle 3 · 0⤊ 0⤋
Lil, you're probably right, but depends on how many were drinking! Jimmy.
2007-09-25 11:13:51 · answer #9 · answered by Jimmy 6 · 0⤊ 0⤋
Depends on the kind of friends you have.
2007-09-25 10:55:21 · answer #10 · answered by Anonymous · 0⤊ 0⤋
depends on how many people there are, alcohol content, and how much each person ate before arriving.
2007-09-25 10:55:24 · answer #11 · answered by Bistro 7 · 0⤊ 0⤋