How do you find maximum height from initial velocity at an angle?

Question

suppose an object has an initial velocity of 15m/s, at an angle of 30 degrees from the x-axis. what is the maximum height the object will go?

Answer 1

It's all in the vertical velocity component Vv = v0sin(theta).
From h = gt^2/2 you get h = Vv^2/(2g).