A lion eats a zebra within 1 hour
A jaguar eats a zebra within 2 hours
A hyena eats a zebra within 6 hours
How long would it take if all three predators nicely ate the same zebra all at once?
I know this sounds stupid, but it's actually part of my math homework and I can't figure it out! Drives me crazy!
Please help me!
2007-09-25 10:18:43 · 4 answers · asked by .:: me ~* 3 in Science & Mathematics ➔ Mathematics
Lions consume zebras at the rate of 1 zebra/hour
Jaguars consume zebras at the rate of 1/2 zebras/hour
Hyenas consume zebras at the rate of 1/6 zebra/hour
If all three eat the same zebra at once, they will consume it at the rate of (1+1/2+1/6) zebras/hour, which is 5/3 zebras/hour. Therefore, to consume 1 zebra, it will take them 1/(5/3) = 3/5 of an hour, or 36 minutes.
2007-09-25 10:29:23 · answer #1 · answered by Pascal 7 · 1⤊ 0⤋
Lion = 1 zebra in 1 hour or 6 zebras in 6 hours
Jaguar = 1 zebra in 2 hours or 3 zebras in 6 hours
Hyena = 1 zebra in 6 hours or 1 zebra in 6 hours
That means the three of them could eat a total of 10 zebras in 6 hours.
6 hours = 360 minutes divided by 10 zebras = 36 minutes per zebra.
2007-09-25 17:31:36 · answer #2 · answered by Kathryn 6 · 1⤊ 0⤋
These rate problems drive me crazy too lol. I think it use to take me 20 minutes to think it out.
Let rate lion is eating at = z / hr
Rate jaguar eats a zebra = z / 2hr
Rate hyena eats a zebra = z / 6hr
6z / 6hr + 3z / 6hr + z / 6hr = 10z / hr
10z / 6hr * t = z
t = 6hr / 10
0.6hr = time
36 min = time
2007-09-25 17:25:28 · answer #3 · answered by UnknownD 6 · 1⤊ 1⤋
who is your teacher!! crazy question!
2007-09-25 17:23:29 · answer #4 · answered by steph 2 · 0⤊ 1⤋