--Math question that im stuck on,,, any answers
2007-09-25 10:11:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i already have 99+100+101
2007-09-25 10:16:50 · update #1
There are many answers:
1)
99+100+101
2)
58+59+60+61+62
3)
13+14+15+16+17+18+19+20+21+
22+23+24+25+26+27
4)
Adding 1 to 24 also results in 300
2007-09-25 10:25:29 · answer #1 · answered by truthseeker 2 · 0⤊ 0⤋
99 + 100 + 101
2007-09-25 10:14:16 · answer #2 · answered by A.Mercer 7 · 1⤊ 0⤋
n + n + 1 = 300
2n + 1 = 300
2n = 299, not going to be a whole number
n + n + 1 + n + 2 = 300
3n + 3 = 300
3n = 297
n = 99
the 3 numbers are; 99, 100, 101
2007-09-25 10:14:51 · answer #3 · answered by sfroggy5 6 · 1⤊ 0⤋
99+100+101
2007-09-25 10:14:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋
It can't be 2 consecutive numbers, because that would be an odd number plus an even number, which is always an odd number. So it has to be 3 or more.
If n is the smallest of these, then n+1 is the next number and n+2 is the one after that. So n + (n+1) + (n+2) = 300. Solve for n, then write n, n+1, n+2.
2007-09-25 10:16:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋