A student presses a book between his hands, as the drawing indicates. The forces that he exerts on the front and back covers of the book are perpendicular to the book and are horizontal. The book weighs 37 N. The coefficient of static friction between his hands and the book is 0.44. To keep the book from falling, what is the magnitude of the minimum pressing force that each hand must exert?
2007-09-25 10:10:39 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Each hand must push with 42.045 N of pressure.
The force up is equal to :
.44* (unknown force) * 2
The force down equals 37 N, so you set the two equal to each other, and solve for unknown
.44* (unknown force) * 2 = 37
37/.88= 42.045
2007-09-25 10:20:40 · answer #1 · answered by Anonymous · 0⤊ 0⤋
37N/ .44 = 84N.
2007-09-25 17:14:48 · answer #2 · answered by jimmymae2000 7 · 0⤊ 0⤋