express the answer in intervals. ***intervals as in inf and cup signs**
2007-09-25 09:52:13 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x(10x+9) > 19
10x^2 + 9x -19 > 0
solve
10x^2 + 9x -19 = 0
=>(10x+19)(x-1)=0
=> x = -19/10 OR x= 1
since +x^2 graph => U shaped
x(10x+9) > 19
=> x =< -19/10 Or x>= 1
2007-09-25 09:56:53 · answer #1 · answered by harry m 6 · 0⤊ 0⤋
10x² + 9x >= 19
10x² + 9x - 19 >= 0
(10x + 19)(x - 1) >= 0
x <= -19/10
or
x >= 1
2007-09-25 16:57:06 · answer #2 · answered by Dave 6 · 0⤊ 0⤋
x(10x+9) >= 19
10x^2 +9x -19 >= 0
(10x+19)(x-1)>=0
So [1, +infinity) U (-infinity,-1.9]
2007-09-25 17:10:45 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
x(10x+9)>=19
10x^2+9x-19>=0
(10x+19)(x-1)>=0
x<= -1.9 or x>=1
2007-09-25 16:58:51 · answer #4 · answered by barakota 1 · 0⤊ 0⤋
x(10x+9) = 19
/x /x
10+9 = 19/x
19 = 19/x
(x) (x)
19x = 19
2007-09-25 16:58:09 · answer #5 · answered by noelle 1 · 0⤊ 0⤋
x > or = to 1 or 1.9
2007-09-25 17:00:48 · answer #6 · answered by Fredster 2 · 0⤊ 0⤋