Through (-5,3), parallel to 4x + 3y = -32
2007-09-25 09:39:22 · 7 answers · asked by william5000forever 2 in Science & Mathematics ➔ Mathematics
Parallel lines have the same slope, so the first thing to do is find the slope of 4x+3y=-32. You can do this my solving for y, so that it is in y=mx+b form where m=slope.
4x + 3y = -32 subtract 4x from both sides
3y = -4x -32 divide through by 3
y = (-4/3)x - 32/3
Now we have the slope as m = -4/3.
From here we can use the point (-5,3) to get the the "b" in y=mx+b which is the intercept.
3 = (-4/3)(-5) + b substituting -5 for x and 3 for y,
3 = 20/3 + b subtract 20/3 from both sides (change 3=9/3)
9/3 - 20/3 = b
b = -11/3
At last, y = mx + b, is slope-intercept form and we have both the m and the b:
y = -4/3 x + -11/3
That's it!
2007-09-25 09:52:12 · answer #1 · answered by Marley K 7 · 0⤊ 0⤋
parallel traces have a similar slope so first enable's get the equation for the 1st line y = mx + b 4x + 3y = -32 3y = -4x - 32 y = -4/3x - 32/3 so the slope of the two traces is -4/3 y = -4/3 x + b 3 = -4/3 * -5 + b 3 = 20/3 + b 3- 20/3 = b -11/3 = b y=-4/3x - 11/3
2016-11-06 08:53:05 · answer #2 · answered by ? 4 · 0⤊ 0⤋
A line parallel to 4x+3y=-32 is of the form:
4x+3y+k=0
If it passes through (-5,3), then
4(-5)+3*3+k=0
-20+9+k=0
k=11
the desired Eq. is
4x+3y+11=0. ANS.
2007-09-25 09:47:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
parallel lines have the same slope so first let's get the equation for the first line
y = mx + b
4x + 3y = -32
3y = -4x - 32
y = -4/3x - 32/3
so the slope of both lines is -4/3
y = -4/3 x + b
3 = -4/3 * -5 + b
3 = 20/3 + b
3- 20/3 = b
-11/3 = b
y=-4/3x - 11/3
2007-09-25 09:47:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋
parallel to the given line means that the slope is -A/B, -4/3.
And it runs through the point (-5, 3).
In point slope form:
y-3 = -4/3 (x+5)
y= -4/3x - 20/3+3
y= -4/3x - 11/3
2007-09-25 09:43:54 · answer #5 · answered by sayamiam 6 · 0⤊ 0⤋
4x+3y =-32 has a slope of -4/3
So our line must also have a slope of -4/3
y = -4/3x +b
3= (-4/3)*(-5) +b
b = 3- 20/3 = -11/3
So y= -4x/3 - 11/3
2007-09-25 09:46:58 · answer #6 · answered by ironduke8159 7 · 0⤊ 0⤋
solve 4x + 3y = -32 for y to find the slope
3y = -4x - 32
y = -4/3 x - 32/3; slope is -4/3
Now we need to find the y-intercept.
Our equation so far is y = -4/3 x + b
Plug in the given number above and solve for b.
3 = -4/3 (-5) + b
3 = 6 2/3 + b
-3 2/3 = b
The equation
y = -4/3 x - 3 2/3
2007-09-25 09:43:12 · answer #7 · answered by sfroggy5 6 · 0⤊ 2⤋