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1. 13e^-(cos(x)) sin(x) dx

** sin(x) is not part of the exponent
[ 0 , pi/2]

2007-09-25 09:30:33 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Int 13e^-(cos(x)) sin(x) dx

let u = -cos(x)
du = sin(x)dx

Int = Int 13 e^u du
= 13 e^u + C
= 13 e^-cos(x) + C

2007-09-25 09:34:28 · answer #1 · answered by vlee1225 6 · 0 0

Well..... I see it as 13e^(-cos(x)) from 0 to π/2. Now it's just plug 'n chug.

Doug

2007-09-25 16:37:53 · answer #2 · answered by doug_donaghue 7 · 0 0

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