Chemistry help!?

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Determine the empirical formulas for each of the following compounds, using the information given.
2.46g of copper is reacted with excess chloride to produce 5.22g sample of copper chloride.

2007-09-25 09:28:47 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

Since all the copper was used up, the molar mass of the resulting copper chloride is more than twice that of copper. Since the molar mass of CuCl is less than twice the molar mass of CU, it is CuCl2.

2007-09-25 09:35:21 · answer #1 · answered by atrichtch 2 · 0⤊ 0⤋

5.22gCu-chloride - 2.46gCu = 2.76g Chlorine

Atomic weights: Cu=63.5 Cl=35.5

2.46gCu/63.5 = 0.0387

2.76gCl/35.5 = 0.0777

0.0387/0.0387 = 1.000

0.0777/0.0387 = 2.009

So the empirical formula is CuCl2

2007-09-25 16:44:12 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋