What is the velocity of this problem?

Question

A bunny is moving across the ice at a rate of 3.83 m/s (squared). The bunny comes to a stop 12.3 meters across the frozen ice. What is the initial velocity of the bunny? The answer is not 0.

Answer 1

a= 3.83 m/s^2
x= 12.3 m
V = 0 m/s
Vo = ??

V^2 = Vo^2 +2ax
0 = Vo^2 + (2)(12.3)(3.83)
Vo^2 = 94.218

Vo= 9.707 m/s

Answer 2

The bunny is --NOT-- 'moving across the ice at a rate of 3.83 m/s²' any more than it is moving across the ice at a rate of 6 kg. If you don't use the right words (and, in this case, the right units) then you don't have a prayer in hell of ever understanding he subject. m/s² are the dimensions of acceleration (or deceleration).
And the bunnies initial velocity was 9.7 m/s (Now it's up to -you- to do a bit of studying and figure out how to come up with that answer)

Doug

Answer 3

acceleration = - 3.83 m/s^2
(The acc is -ve because it comes to a stop)
Let v0 = inital velocity
v1 = final velocity = 0

To solve this, use this trick in textbook

dv/dt = a
(dv/ds)(ds/dt) = a
(dv/ds)v = a
v dv = a ds
integrating
v^2/2 = as to be evaluated between the limits
v1^2 - v0^2 = 2as
0 - v0^2 = 2 (-3.83) (12.3)
v0^2 = 7.66(12.3) = 94.22
v0 = 9.7

Ans inital velocity = 9.7 m/s

Answer 4

u=?, v=0,
a=-3.83m/s^2,s=12.3m
using :
v^2=u^2+2as;
0=u^2-2*3.83*12.3
u^2=2*3.83(12.3=94.22
u =9.7m/s

Answer 5

3.83 m/s^2