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So far I made it 1/2y=-x

Do I multiply the -x by the denominator of 1/2y? That would give me y=-2x/1 and my slope would be -2 over 1. Is that right? The only problem there seems to be no y intercept so I am a bit confused.

2007-09-25 08:06:20 · 9 answers · asked by Nicholas L 1 in Science & Mathematics Mathematics

9 answers

x = (-1/2) y
2x = - y
y = - 2x
To draw this straight line , two points are required.
(0 , 0) and (5 , - 10) would be suitable points.
Line passes thro` the origin (0 , 0)

2007-09-29 07:54:29 · answer #1 · answered by Como 7 · 0 0

x= -1/2y
multiply both sides by the reciprocal of -1/2 which is just -2 and that will give you just y on the right
-2x=y is the same as y=-2x
In the slope intercept form, the slope is -2 and since y=-2x is the same as y=-2x+0 the y intercept is zero. Basically then, you can start at the origin (0,0) and rise negative two and run one (in other words a negative rise means you are moving down instead of up). You can also do a positive rise of 2 and just do a negative run (moving to the left) as well (as long as the signs are opposite, you will still have a -2).

To test it out, plug in a few points:
we know 0,0 already
if x=1 then y must be -1/2 of 1 or just -1/2 giving you (1, -1/2)
if y=1 then 1=-2x so x = -1/2) (-1/2, 1)

If these points fall on the line you graphed, then you know you are correct.

2007-09-25 08:22:33 · answer #2 · answered by cgflann 4 · 0 0

Okay, here is how you do it:
x=-1/2y You divide both sides by -1/2
y=-2x
This means that the slope will be -2 and the y-intercept is automatically 0 ( which means the line will go through the origin in the graph).

2007-09-25 08:14:14 · answer #3 · answered by Anonymous · 0 0

Let's assume we are plotting x along the horizontal axis and y along the vertical one. Then we need to write the equation as
y is a function of x. y = f(x). You must get y in the numerator on one side of the equation alone.

x=-y/2 OK with this so far?
-1*x=(-1)*(-y/2)=y/2
2*(-x)=2*(y/2) =y rewriting

y = -2x y intercept is when x=0
so y intercept =0

2007-09-25 08:20:01 · answer #4 · answered by Tony G 2 · 0 0

the equation give is in the slope intercept form... but it shows the y intercept... we can rearrange that to form it in a equation where the x intercept is shown... y = -2x + 4 y -4 = -2x x = -1/2 y + 2 where: 2 is the x intercept

2016-04-06 00:46:26 · answer #5 · answered by Anonymous · 0 0

if there is no y intercept or in other words the value of y intercept is 0 then the line is passing through the origin
your equation is correct
i.e y=-2x
just substitute values for x and get the corresponding values of y and plot the graph

the line will pass through the origin and the 2nd and 4th quadrant

2007-09-25 08:16:54 · answer #6 · answered by 222 3 · 0 0

You are correct. The equation in 'normal' form is:

y = -2x

you can always write it as: y = -2x + 0
if you want to see that the y-intercept is at 0.

.

2007-09-25 08:22:42 · answer #7 · answered by tlbs101 7 · 0 0

1/2y=- X
Y=-2X if y=1 X=-1/2
if x=1 Y=-2
And graph is downward (negative slope).
(0,-2) and (-1/2,0)

2007-09-25 08:25:22 · answer #8 · answered by Anonymous · 0 0

okay, you have 1/2y = -x
make it y = -2x

That is much easier to graph.

2007-09-25 08:19:09 · answer #9 · answered by soelo 5 · 0 0

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