In total, the squirrel walks 12 feet. 9 inches into 12 feet goes 16, so 16 acorns were buried. (We do not need to worry about end-points as the path is a cycle)
2007-09-25 06:49:32
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answer #1
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answered by Mr. Name 2
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I had to look at your question. I didn't know what squirrel math was.
Draw a square ABCD.
At A put a dot, If AB = 36 inches long, there are 4 intervals of 9' each at which points acorns are put, but you have a starting point and a finishing one, therefore there are 5 such points. On BC there are 5 also, except we're already counted the one at B so you only get 4 new ones. Same for CD. Now at DA you get 5 again but D was already counted, and A was already counted, so you finally end up with 5 + 4 + 4 + 3 =16.
2007-09-25 13:55:08
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answer #2
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answered by rrsvvc 4
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Let's consider a line. He buries one at 0, 9, 18, 27, and 36 inches in the line. That's five acorns. There are four sides...so, that's twenty acorns.
But wait! We double-counted the corners...because acorn 0 of one line is acorn 36 of the other. So, there are actually 16 acorns buried.
2007-09-25 13:51:28
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answer #3
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answered by PMP 5
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Since 3 feet = 36 inches, and the acorns are 9 inches apart, there are 5 acorns at each side (4 spaces, each 9 inches); note that I counted corner acorns twice.
The following figure shows the solution: ( * = acorns, - = empty space)
* * * * *
* - - - *
* - - - *
* - - - *
* * * * *
There are 5 + 3 + 3 + 5 = 16 acorns.
2007-09-25 13:57:36
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answer #4
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answered by jcastro 6
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OK
Key is to see that 3 feet = 36 in. and 36 in/9 = 4.
So in the first side he buries 5 acorns, then he buries 4 then 4 more and the last side he buries 3.
So the total he buries? 16.
Draw it for yourself and you will see!
Hope this helps.
2007-09-25 13:51:56
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answer #5
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answered by pyz01 7
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16.
4 corners plus 3 in between on each side
4 + 12 = 16
2007-09-25 13:48:34
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answer #6
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answered by Matt C 3
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roll up deep into this steeze, that's what it sez. ace!
2007-09-25 13:54:19
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answer #7
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answered by Spicoli 4
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