int (-infinity, 0) 1dx/(2x-5)
2007-09-25 06:16:21 · 3 answers · asked by sugardaddy8815 1 in Science & Mathematics ➔ Mathematics
It's divergent. The indefinite integral is...
1/2*log(2*x - 5)
...and this becomes increasingly negative without bounds for your lower limit of integration.
2007-09-25 06:21:37 · answer #1 · answered by PMP 5 · 0⤊ 0⤋
The integral is 1/2(- ln I 2a-5I + ln 5) and this ===> -infinity if a ===> -infinity so the integral is divergent
2007-09-25 06:44:24 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
it is convergent by using fact the region the place the integrand, the expression interior the vital, is going to infinity is -3 this is outdoors one in all those integration. to evaluate it, placed z = x+3, dz = dx and x going from 2 to infinity makes z go from 5 to infinity. The vital reduces to int(5, infinity) z^(-3/2) dz, this is comparable to 0 - 5^(-a million/2)/(-a million/2) . it is two/sqrt(5)
2016-12-17 10:00:07 · answer #3 · answered by friedman 4 · 0⤊ 0⤋