If we order a large pizza (16" diameter) and slice it into 12 slices, what is the area of one piece?
2007-09-25 06:06:04 · 6 answers · asked by Nicky 2 in Science & Mathematics ➔ Mathematics
Assuming the pizza is a circle and the pieces are equal :
16 inch diameter
So 8 inch radius (since radius is 1/2 the diameter)
Area of a circle is pi * radius^2
= pi * 64
So The area of one slice is (64/12) * pi, which is (16/3) pi, around 16.755 square inches.
I think.
2007-09-25 06:09:33 · answer #1 · answered by rahidz2003 6 · 0⤊ 0⤋
No Trig. Geometry. Area of a circle is Radius squared times pi. A = r^2 X {pi} Given diameter is 16", radius = 8".
A = 8^2 X 22/7 = 201.14
Circle has 360 degrees. 1/12 of 360 = 30 degrees.
30/360 = 1/12 of total area of circle. Thus, 1/12 X 201.14 = 16.76 or rounded off to 17 square in/slice. The answer for all practical purposes is correct but is an approximation due to the use of decimals.
2007-09-25 07:00:02 · answer #2 · answered by gzlakewood@sbcglobal.net 4 · 0⤊ 0⤋
Are you sure this is a trig problem ?
area of a pizza with a 16" diameter is pi r^2 r=8 r^2=64
64 (3.1416) = 201.0624
201.0624 / 12 = 16.7552 square inches
2007-09-25 06:16:32 · answer #3 · answered by Will 4 · 0⤊ 0⤋
Hello
The area of the pizza is pi(r^2)
So the area of a pizza with diameter of 16" is
64pi = 201.06 in squared.
So if the pieces are all congruent then we have 201.06/12 = 16.76 square inches of pizza.
Hope this helps
2007-09-25 06:10:34 · answer #4 · answered by Jeff U 4 · 0⤊ 0⤋
sin² x + cos x - 1 = 0 1 - cos² x + cos x - 1 = 0 -cos² x + cos x = 0 cos² x - cos x = 0 cos x(cos x - 1) = 0 cos x = 0 x = arccos(0) = π/2, 3π/2 (cos x - 1) = 0 cos x = 1 x = arccos(1) = 0, 2π
2016-05-18 02:09:42 · answer #5 · answered by ? 3 · 0⤊ 0⤋
1.4"
2007-09-25 06:30:40 · answer #6 · answered by angelinaroddd 3 · 0⤊ 0⤋