what are the 3 co ordinates of f(x)=x(x-4)(x+2)....
i know that the 3 co ordinates of, say, f(x)=(x-2)(x-3)(x-1) are 2, 3, and 1. But I'm not sure when there aren't 3 set brackets like in the question.
Thanks
2007-09-25 04:20:50 · 5 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics
It has been a long time since I studied this and I don't believe that co coordinate was in use at that time, but I think you mean what values of x will make f(x) = 0
f(x) = x * (x-4) * (x+2)
(x=0) (x=4) (x=-2)
2007-09-25 04:35:36 · answer #1 · answered by Tony G 2 · 0⤊ 0⤋
I think you mean the three ZEroS, because, usually, it is written: f(x) = etc ... = 0.
For x(x-4)(x+2) = 0, this happens when
x=0 | x-4 = 0 | x+2 = 0 or
x= 0 | x=4 | x=-2.
2007-09-25 04:29:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a million). (2x^2 + 7x - 36)/x + 7 = 2x - 7 + 13/ x + 7, ultimate 13 2). (2y^2 - 4y - 2)/(2y + 2) = y^2 - y - a million 3.(2y^4-y^3+7y-2)/(2y + 3) = y^3-2y+3y-a million, ultimate a million 4.(3y^3 - 9y - 6)/(3y + 3) = y^2 - y - 2 5.(b^5 - b^4 +6b^2 -5b +3)/b^2 -2b + 3 = b^3 +b^2 - b +a million 6. a^5 + 32/a -2 = a^4 + ^2a^3 + 4a^2 + 8a + sixteen, ultimate sixty 4.
2016-11-06 08:15:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
it doesn't matter if there is no bracket for the first x. the x-intercepts are (0,0) (4,0) and (-2,0). Do the same as u did for the 2nd f(x) eqn
2007-09-25 04:28:38 · answer #4 · answered by sp 1 · 0⤊ 0⤋
0,4,and -2
2007-09-25 04:30:09 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋