radical of(x-1) + radical of(y-2) + radical of(z-3) + 5.25 = x+y+z
i need to find out x, y and z
yeah... im not american or english and i hope i wrote it correctly 'radical of' cause i dont know how to make the symbol on a keyboard...
2007-09-25 03:29:41 · 3 answers · asked by paolomoldovan789 2 in Science & Mathematics ➔ Mathematics
well, i dont really know i just need to find the solution... and yes its square root.
2007-09-25 04:04:44 · update #1
the problem says that i need to find the real numbers x, y and z
2007-09-25 04:10:30 · update #2
(x-1)- sqrt(x-1)+1/4 + (y-2) -sqrt(y-2)+1/4 +(z-3)-sqrt(z-3)+1/4 +
1+2+3-3/4 -5.25=0
((sqrt(x-1)-1/2)^2 +(sqrt(y-2)-1/2)^2+
(sqrt(z-3)^2-1/2)^2 =0
that means under square all numbers are 0, you solve the equations
2007-09-25 04:23:00 · answer #1 · answered by Theta40 7 · 0⤊ 0⤋
I don't know how to make the symbol either! Sometimes I use "sqrt(x)" for "square root of x".
Now, I think there must be more to the problem than you stated, because it actually has infinitely many solutions.
Were there additional conditions in the problem? For example, are x, y and z constrained to be rational numbers?
2007-09-25 10:39:09 · answer #2 · answered by RickB 7 · 0⤊ 0⤋
does radical mean square root?
2007-09-25 11:02:45 · answer #3 · answered by trogwolf 3 · 0⤊ 0⤋