2007-09-25 03:03:24 · 4 answers · asked by daineyjinh 1 in Science & Mathematics ➔ Physics
The buoyant force is always exactly equal to the weight of the displaced fluid.
So, first you need to know the volume V of the immersed object.
Then you need to figure out, how much would an equal volume V of water weight?
Weight = (mass) x (gravity)
= (density) x (volume) x (gravity)
The density of water is 1000 kg/m^3, and gravity is 9.8 m/sec²
Now all you need is the object's volume in cubic meters. Plug that into the formula, and you get the buoyant force in Newtons.
2007-09-25 03:21:50 · answer #1 · answered by RickB 7 · 1⤊ 0⤋
Bouyant force is equal to the volume of the fluid displaced times the density of the fluid divided by the local gravitational field. Doug EDIT: For pure genius: How do you express volume in Newtons? You seem to be suffering from the usual confusion between 'weight','mass', and 'force'. They are three -totally- different things.
2016-05-18 01:02:10 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Measure the volume of water displaced by the object ...
how high it rises multiplied by the surface area of the container. The weight of the water displaced is the bouyant force. Water weights 1g/cm^3.
If the object floats, then you have displaced exactly the weight of the object.
2007-09-25 03:23:43 · answer #3 · answered by dooner75 3 · 1⤊ 0⤋
Weight out of water - weight in water
2nd measurement taken with this:
http://s223.photobucket.com/albums/dd78/floodtl/?action=view¤t=buoyancy.jpg
2007-09-25 03:29:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋