2u^2 - 5u - 3 = 0
Help factor please
2007-09-25 00:16:31 · 4 answers · asked by K Rose 3 in Science & Mathematics ➔ Mathematics
2u² - 5u - 3 - 0
The middle term is - 5u
Find the sum of the middle term
Multiply the first term 2 times the last term - 3 equals - 6 and factor
The factors of - 6
1 + - 6. . .←. .us these factors
- 2 + - 3
- 6 and + 1 satisft the sum of the middle term
insert - 6u and + 1u into the equation
2u² - 5u - 3 = 0
2u² - 6u + 1u - 3 = 0
Group factor
(2u² - 6u) + (1u - 3) = 0
2u(u - 3) + 1(u - 3) = 0
(2u + 1)(u - 3) = 0
- - - - - - - - -s-
2007-09-25 00:57:22 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
2u^2-6u+u-3=0
2u(u-3)+1(u-3)=0
(2u+1) (u-3)=0 : Factors
2u+1=0, u-3=0
u= -1/2, u=3: solved for u
2007-09-25 07:27:18 · answer #2 · answered by titu 2 · 0⤊ 0⤋
it would be :
2u^2 - 5u - 3 =0;
(2u+1)(u-3) = 0
ok!
2007-09-25 07:21:42 · answer #3 · answered by david m 2 · 0⤊ 0⤋
2u^2-5u-3=0
2u^2-6u+u-3=0
2u(u-3)+1(u-3)=0
(2u+1) (u-3)=0
2007-09-25 07:23:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋