please give me the formulae for head calculation of pump and how to calculate the water requirement??

Question

its a plumbing question

Answer 1

Since you're not specific on your application, check out this site.

http://en.wikipedia.org/wiki/Bernoulli's_principle

As for water requirement, are you plumbing to a bathtub, drinking fountain, garden hose, etc? It all depends on what you want to do.

Answer 2

Hi
Its difficult to determine what it is you are after, the static head(vertical lift) can be caculated by just adding all the vertical pipes up, but the resistive head is caculated but knowing the size( internal bore ID) of pipe you are using the loss figure of the material of the pipe for a given length and finally the quantity of liquid to be pumped ie ltrs/sec .
So really more information required.
Look at
http://en.wikipedia.org/wiki/Head_(hydraulic)

Regards
John

Answer 3

See the following web site for a detailed discussion of pump head:

http://www.fluidh.com/WebCalcPumpHead.htm

Answer 4

if "Q" is the discharge,"h" is the head..........
from the velocity diagrams find out necessary parameters like vw1&vw2(whirl components of velocity),(vf1 &vf2 flow velocities)
then calculate h as follows
if given efficiency "n"
then n =gh/(vw1*u1-vw2-u2)
where u1=pie *innerdia*speed(in r.p.m)/60
u1=pie *outerdia*speed(in r.p.m)/60

power = vw1u1-vw2u2 =wQh (where w =density *9.81)
knowing the values of vw1,vw2,u1,u2,w,h.........we can get the discharge from the equation..
i cant get proper information from ur question..if u have further or more information,ten i will be able to help u...