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I have a rod attached to a plate and I am rotating the rod through 180 degrees. The rod is 6 inches long, attaches to a plate of 2X2 inches. The material is solid copper on both. Rod diameter is 1". The plate is fixed to a concrete slab and it will not move but I need to determine the shear force to tear away the pipe

2007-09-24 16:19:23 · 2 answers · asked by J B 1 in Science & Mathematics Engineering

2 answers

The maximum shear force occurs on the surface of the rod. The formula for shear force in a rod under torsion, (assuming no stress concentrations, and that the system fails by the rod failing under shear torsional force) is t=16T/piD^3

Where t = torsional stress
D= diameter
and T= torque.

Annealed copper has an ultimate tension strength of 32000 psi (Wolf 465). Ultimate shear strength will be approximately 16000 psi.

So,

16000 psi = 16*T/pi therefore
16000 psi*pi/16 = T
and T=3140 lb*in.

2007-09-24 19:41:23 · answer #1 · answered by Anonymous · 0 0

The reactions on the top of the beam are P/2 that's additionally the shear on the help. As that's a element load the shear would be consistent at useful (counting on your sign convention) P/2 on the element load this could then bypass to adverse P/2 and stay at this till the top of the beam. The bending 2d diagram is triangular formed with a max of PL/4.

2016-10-09 19:23:38 · answer #2 · answered by ? 3 · 0 0

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