If I have a single phase 200 Amp panel with phase "A" loaded at 24 amps and phase "B" loaded at 14 amps, would that make my total load at 120 Volts 36 amps? and then to convert that to 240 volts would I simply take the VA of 4320 VA @ 120V and divide by 240? That seems way too low. The problem is that all I have are the reading from the two legs of this panel, A & B... I need to know what the total load is with these two readings. These are radio panels so everything being powered is continuous, 80% rule mind you.
Thanks
2007-09-24 12:41:39 · 3 answers · asked by alex_blanding2001 1 in Science & Mathematics ➔ Engineering
Your calculations are completely correct.
The load you measured is 4320 VA. If the load was perfectly balanced between the two legs, the load would be 4320 VA ÷ 240 V = 18 A.
Remember that you cannot load either leg beyond 80% of its rating.
2007-09-24 13:21:59 · answer #1 · answered by Thomas C 6 · 1⤊ 0⤋
Your load would need to be based on a 240 volt supply with a current draw of 36 amps, but unbalanced by 10 amps. All f this needs to be considered for the VA figure. I think you need to revisit your figures. It is a supply of 240 volts with an unbalanced load of 36 amps, not 120 volts at 36 amps. Phase A is going to have a phase difference from phase B since they are on opposite sides of the power transformer.
2007-09-24 15:10:52 · answer #2 · answered by Anonymous · 0⤊ 2⤋
Assuming a center tapped transformer with 2 warm conductors, a hundred and eighty stages out of section: via balancing the burden between the two warm buses, you're lowering the impartial load. you're procuring the potential required to push the present in the process the resistance of the impartial conductor. If the burden on each and every warm bus is balanced, there isn't any impartial load.
2017-01-02 15:31:44 · answer #3 · answered by ? 4 · 0⤊ 0⤋