Series parallel resistor circuit...?

Question

What is the total Resistance of this Circuit.
All Resistors are in Ohms.
And what is the Current flowing through it, also what is the Power dissipation in Watts...?

http://bp3.blogger.com/_3dHP_CJrEXQ/Rvglq_miQfI/AAAAAAAAAAs/HMgoThY5NYc/s1600-h/resistor.jpg
or
http://wwwemcsquared.blogspot.com/

Voltage = 100v

the number of the beast by the way...lol

LOL..yea ok...but it works out to above...

Answer 1

You just need to work on it one step at a time. For example, the easiest thing to do first is to add up the resistors that are simply in series, and replace them with a single resistor with the total resistance.

R1 + R2 = 15
R3 + R4 = 120
R6 + R7 = 140
R8 + R9 = 50

Now you have a circuit with 2 resistors in parallel in series with a single resistor in series with another two in parallel. Now combine the parallel resistors into single equivalent resistors.

1/Req = 1/15 + 1/120 = 13.33
1/Req = 1/140 + 1/50 = 36.8

Now you have three resistors in series, so just add them all up.

Rtotal = 150.1

Current:
V = I x R
I = V / R = 0.666 amp

Power:
P = I^2 x R = 66.6 watt

Answer 2

I assume that you already knew how to combine the total resistance between series and parallel conections. The voltage across each resistor may not equal with each other for series connection while parallel does.And for about current.you may find total resistance and the current ,you will know the answer. And the other thing is,if a resistor in series circuit burnt out,the current may not flow.This means that circuit doesn't work anymore(no current at all, just like a switch is turned off), while for parallel connections,the current can flow throu another resistor(s). The above explaination is assumed that you deal with DC circuits and simple connections.There are more complex if you deal with AC circuits since it has amplitude and phase. Does this help?

Answer 3

1. Find the parallel combination of the left side.

10+5 = 15
20+100 = 120
15 parallel with 120 --> 1 / (1/15 + 1/120) = 13.3333 Ohms

You can do the right side with this example.

Then add them up
R = 13.333 + 100 + what you get for the right side

You'll make good use of the [1/X] button on your calculator.

2. Ohms law
V = I * R
V = 100
R is what you get above
I is the current

3. Power law
P = V^2 / R
P = I^2 * R
both give the same answer

Answer 4

I'll solve it for you if you'll add to your blog resume that you're too damned stupid to figure out simple Ohms Law problems.

R1 in series with R2 = R1 + R2 (call it Rx)
R3 in series with R4 = R3 + R4 (call it Ry)
Rx in parallel with Ry is 1/((1/rx) + (1/Ry)) (call ir Rz)
Rz in series with R5 is Rz + R5
Now treat R6, R7, R8, and R9 just like you did R1, R2, R3, and R4 to get their equivalent resistance and stuff it in series with Rz and R5 to get the total resistance. Divide the battery voltage by the total resistance to get the total current. Multiply the total current by hte battery voltage to get the power consumption.

Doug

Answer 5

For the one who says that he is too damned stupid?..That might apply to you if you don't know who you are talking to or about!...Ever occur to you he may be asking to see how smart you are or not? (Talking about the one who says he'll work out the problem because he's too damned stupid?)

Answer 6

Homework time is it?

Answer 7

cant you ask a difficult question now and then?