calculus ???

Question

Can you guys help me with this ?

find the horizontal and vertical asymptote of this curve

y = (x^2 + 1)/ (2x^2 - 3x -2)

Answer 1

y = (x^2 + 1) / (2x^2 - 3x -2)
y = (x^2 + 1) / (2x - 1)(x + 2)
Vertical asymptotes at
x = 1/2, - 2
y = 1/(2 - (5x + 2)/(x^2 + 1))
Horizontal asymptote at y = 1/2