Can Someone help me please with my algebra HOMEWORk?

Question

Can you please show me step by step how to do the following equations PLEASE!!!


4(2y - 4) = 5y + 2

-6 - -2n = 3n - (6 + 5)

8(x - 3) + 8 = 5x - 22

Answer 1

4(2y - 4) = 5y + 2 First, multiply through by 4 on the left side to remove the parentheses.

4(2y - 4) = 5y + 2
8y - 16 = 5y + 2 Now, collect y's on one side and the constants on the other. First, we'll subtract 5y from each side.

4(2y - 4) = 5y + 2
8y - 16 = 5y + 2
8y - 5y -16 = 5y - 5y + 2
3y -16 = 2 Next, we'll add 16 to both sides.

4(2y - 4) = 5y + 2
8y - 16 = 5y + 2
8y - 5y -16 = 5y - 5y + 2
3y -16 = 2
3y - 16 + 16 = 2 + 16
3y = 18 Lastly divide both side by 3
3y/3 = 18/3
y = 6.

HTH

Charles

Answer 2

If solving for the variables:

1] 4(2y - 4) = 5y + 2
8y -16 = 5y +2
8y - 5y - 16 = 5y - 5y + 2
3y -16 = 2
3y - 16 + 16 = 2 + 16
3y = 18
3y/3 = 18/3
y = 6

2] -6 - -2n = 3n - (6 +5)
-6 + 2n = 3n - 11
-6 + 2n - 2n = 3n - 2n - 11
-6 = n - 11
- 6 +11 = n -11 + 11
5 = n
or
n = 5

3] 8(x - 3) + 8 = 5x - 22
8x - 24 + 8 = 5x - 22
8x - 16 = 5x - 22
8x - 5x - 16 = 5x - 5x -22
3x - 16 = -22
3x - 16 + 16 = -22 + 16
3x = -6
3x/3 = -6/3
x = -2

Problem 1 answer : y = 6
Problem 2 answer: n = 5
Problem 3 answer: x = -2


hope this helps!!

Answer 3

for the first question:

4(2y - 4) = 5y + 2

you start with the 4(2y - 4) using the distribution property. the 4 is touching the parenthesis (2y - 4) so you first multiply the 4 by the 2y. (you can multiply unlike terms) you should get 8y. next, you multiply the 4 by the - 4. four times four = 16 to 4 times - 4 = -16. so now instead of 4(2y - 4), you have 8y - 16. now, go to the other side. look at the 5y, it is similar to the term 8y which is on the other side. so, subtract 5y from 8y to get rid of one. you could do it the other way but i recommend doing it this way. this gives you 3y - 16 = 2. now, you have to get rid of the - 16 because the goal in algebra is to get the variable all alone. because the 16 is negative, you have to do the opposite or subtracting. so you add 16 which cancels out the - 16. then do it to the other side giving you 16 + 2 = 18. now you have 3y = 18. find what is common between the two numbers. in this case, it is 3. divide both sides by 3 giving you the final answer. [ y = 6 ]

e-mail me for help with the others: [e-mail]

Answer 4

I'll try to help, if this hasn't already been answered by the time I finish typing!

Yes, first distribute:

4(2y - 4) is the same as 4 x 2y minus 4 x 4, or 8y - 16.

8y - 16 = 5y + 2

Then, you want to get all of the terms containing variables (the "y" terms) onto one side of the equal sign, and the plain ol' numbers on the other side. So, let's subtract 5y from each side:

8y - 16 - 5y = 5y + 2 - 5y
or
3y - 16 = 2

Now, let's add 16 to each side:

3y - 16 + 16 = 2 +16
or
3y = 18

To get y all by itself, divide each side by 3

3y / 3 = 18 / 3
or
y = 6

Does that make sense? Hopefully that will help you figure out the other 2 problems as well!

Answer 5

Do any multiplication to get all single line items.

4(2y-4) would be 8Y-16

Then collect variables on one side of the equation and constants on the other.

so 8Y -5Y since it subtracts to other side and

2- (-16) subtracts but was a negative on other side...which leaves

3Y = 18

That is simple division.....= 6

Next one....put in simple line items.....

-6 --2n would be -6+2n against 3n - 11 (just added them up)

2n-6=3n-11

or

2n-3n= -11--6 or -n=-11+6= -5

so -n = -5 or n =5

catching on?

Multiply it out....

8x-24 +8 = 8x -16 = 5x -22

So 8x -5x =3x = -22--16= -6=3x

I would think x=-2

Hope that helped!

Answer 6

4(2y-4) = 5y + 2
8y-16 = 5y +2
3y =18
y = 6


-6- -2n = 3n -(6+5)
-6+2n = 3n-11
5 = n


8(x-3) +8 =5x-22
8x-24 +8 = 5x-22
8x-16 =5x-22
3x = -6
x = -2

Answer 7

ok number one, multiply 2y and -4 by four. so you have 8y-16=5y+2. then subtract two form both sides so you have 8y-14=5y. then subtract 8y form both sides so you have -14=-3y. Then divide -14 by -3 and get 7 =y.

Number two, add 6 and five so now your equation reads, -6--2n=3n-11. Then add 11 to both sides so u get 5--2n=3n. Then add 2n to three n so you get 5=5n. Then divide 5 by five and get 1=n.

three, multiply 8 by x and -3 so you get, 8x-24+8=5x-22. Then add 8 to 24 so you get 8x-36=5x-22. Then add 22 to both sides and get 8x-58=5x. Then subtract 8x form both sides so you get -36=-3x. Then divide -36 by -3 and get 12=x.

Answer 8

4(2y-4)=5y+2
the key to this is to get the variable on one side and the numbers on the other.
8y-16=5y+2 Distribute
8y=5y+18 added 16 to both sides
3y=18 subtracted 5y from both sides
y=6 divided by three to both sides
Algebra is hard but good luck!

Answer 9

Have you ever seen a set of balance scales? The equal sign stands for an equilibrium that exists between one side and the other. The object of this game is like pick up sticks if you've ever played that or building a house of cards. At any given time, the whole thing has to stay balanced. It's like a game with rules. To play any game you have to follow the rules. You could spend all day questioning the rules and create your own rules, but that's not the scenario. Your teacher and book provide the iron-clad rules of this game algebra and you better pay attention to them if you want a good grade. Like I said the main thing is to get an answer finally, but you have to keep this balance scale from tipping. You do that by treating both sides of the equation equally. What algebra is all about is learning the game rules. There are other branches of mathematics and algebra is just as important, but the rules get more and more involved. When you started to learn games as a kid they didn't start you out on a card game like pinocle or casino. You learned something simple, same thing with algebra. Algebra is important, everyone should know algebra I believe. This is where you start to learn the simplest rules of bigger, better games. I think this problem has been solved for you. I just want to impress on you here, that what you're learning here is a bunch of rules and the name of this game algebra is keeping both sides of the equals sign in equilibrium while doing all these operations, like adding, dividing, multiplying, subtracting. In algebra two, the game is still keeping both sides the equal sign in equilibrium , but then it will include new operations such as square roots and powers of known and unknown quantities.

Answer 10

4(2y-4)=5y+2
(4*2y)-(4*4)=5y+2 use the distributive property.
8y-16=5y+2
-5y+8y=2+16 Move the variables to one side of the equal sign and the numbers to the other. It doesn't matter what side you move them to! Just remember to "add the opposite"
3y=18...always divide by the number in front of the letter!
3y/3=18/3
y=6
The other two problems can be solved the same way. good luck!!!