maybe divide or something!
2007-09-23 13:34:30
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answer #1
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answered by Anonymous
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You can set it up as a quadratic equation in 2 unknowns:
Let L represent the larger part, & S the smaller. Then:
L + S = 150
4L - 5S = 60
Solve #1 for L:
L = 150 - S
Substitute in #2:
4(150 - S) - 5S = 60
Simplify:
600 - 4S - 5S = 60
540 = 9S
S = 60
Substitue in #1
L + 60 = 150
L = 150 - 60 = 90
2007-09-23 20:39:48
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answer #2
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answered by Robert S 7
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Let x = larger part, and (150 - x) be smaller part.
exceeds means is more than which is add. So
4x = 5(150-x) + 60
2007-09-23 20:35:25
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answer #3
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answered by hayharbr 7
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Ninety (90) and Sixty (60).
4 x 90 = 360
5 x 60 = 300
2007-09-23 20:35:38
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answer #4
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answered by Daniel T 5
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Thats easy, you use your functional tables and enter the consign that belongs to the tangent, and then muliply by the coefficient of quandrant that equals the performing product dividided by the answer you get from the simple equation. Wait.......another student needs my help, i'll get back to you on this simple problem after I help another student and attend the Deans meeting at the University of Higher Learning (higher math department).
2007-09-23 20:49:23
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answer #5
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answered by yawlcome2000 3
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divide 150. uhh. hold on....... x is the larger #, y is the smaller...
x + y = 150
4x>5y-60
hmm.. dunno wut to do from there...
okay, lets try, 70 and 80
so 80 is y and 70 is x 70+80+150
4(70)>5(80)-60
280>400-60
280>340....nope 60 off.
okay, x and y have to be like only a couple #'s apart for this to work....
lets try 79 and 71
4(71)>5(79)-60
284>395-60
284>335 52 off
okay, try to make x and y really close together like 74 and 76 then it might work. good luck!!
2007-09-23 20:40:28
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answer #6
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answered by Anonymous
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90 and 60
90x4=360
60x5=300
360-300=60
2007-09-23 20:42:00
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answer #7
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answered by Brian J 1
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150=4X+(5y+60)
2007-09-23 20:35:32
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answer #8
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answered by khrome_wind 5
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150=4X+(5y+60) i think thats what it is
2007-09-23 20:35:34
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answer #9
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answered by ........ 3
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x+y=150
4x=5y+60
x=(5/4)y+15
(5/4)y+15+y=150
(9/4)y=135
y=60
x=90
2007-09-23 20:36:05
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answer #10
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answered by Anonymous
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