so how could i write each equation in point slope form?
point slope form is y2 - y1 = m(x2-x1)
slope -1/4, (7, -5)
slope 5, (-2, 8)
slope -2, (3/1)
2007-09-23 12:45:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You are give the m, and the x1 and y1, so we'll just call y2 "y" and x2 "x".
y - (-5) = (-1/4)(x - 7) =
y + 5 = -x/4 + 7/4
4y + 20 = -x + 7
x + 4y = 7 - 20
x + 4y = -13
That should give you the pattern you need for the others.
HTH
Charles
2007-09-23 12:56:18 · answer #1 · answered by Charles 6 · 0⤊ 0⤋
For each line you have written there is only one point where is the other one?
okay I assume the other point is the origin point (0,0) then the answer well be
(7-0) = -1/4(-5-0)
(-2-0) = 5(8-0)
(3-0) = -2(1-0)
2007-09-23 19:58:21 · answer #2 · answered by Rayan Ghazi Ahmed 4 · 0⤊ 0⤋
slope = m
x-value of ordered pair = x1
y-value of ordered pair = y1
Plug and chug.
Example:
slope -1/4, (7,-5) y + 5 = -1/4 * (x - 7)
2007-09-23 19:52:52 · answer #3 · answered by lhvinny 7 · 0⤊ 0⤋
i got lost after
so how could...
2007-09-23 19:52:53 · answer #4 · answered by [[ yESSiR ]] 2 · 0⤊ 0⤋