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Tension in a string from which a 4.3 kg object is suspened in an elevator is equal to 45N.

What is the magnitude of the acceleration of the elevator?
What is its direction? (I don't know how I would go about answering this question)


m=4.3kg
T=45N
g=-9.8

F=ma=T-mg
a=T-mg/m
a=(45-42.14)/4.3
a=.66512 m/s^2

IS this correct??

2007-09-23 12:39:06 · 1 answers · asked by ? 1 in Science & Mathematics Physics

what about its direction?????

2007-09-23 13:20:52 · update #1

1 answers

F=m*a, so the net acceleration is
45/4.3
a=10.465

Since this is the net, subtract 9.81 to find how much the elevator is accelerating w/r/t Earth
10.465-9.81
0.655

Since you didn't state your value for g, that's the diff.
Did you use 9.8?
0.665 is what I get then

j

2007-09-23 13:12:24 · answer #1 · answered by odu83 7 · 0 0

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