Help Pls!! The height above ground of a toy rocket launched upward from the top of a building is given by.....

Question

The height above ground of a toy rocket launched upward from the top of a building is given by s(t)=(-16t^2)+96t+256.

a) What is the height of the building?
b) What is the maximum height attained by the rocket?
c)Find the time when the rocket strikes the ground.

* Pls include all steps.

Answer 1

a) that is when t = 0, s(0) = 256

b) if you are a calc student, you could find that by finding the turning point using derivative, or use graphing
any case, it reach max height when t = 3

s(3) = 400

c) hit the ground when s(t) = 0
solve -16t^2 + 96t + 256 = 0
(t-8)(t+2) = 0 t= 8 (time cannot be neg)