Copper Sulfide is formed when copper and sulfur are heated together. In this reaction, 127g of copper reacts with 41g of sulfur. After the raction is complete, 9g of sulfur remains unreacted. What is the mass of copper sulfide formed?
2007-09-23 10:28:09 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Atomic weights: Cu=63.5 S=32 CuS=95.5
Cu + S ===> CuS
Because 9g S is left over, Cu is used up first. That is the limiting reagent. So start with Cu first:
127gCu x 1molCu/63.5gCu x 1molCuS/1molCu x 95.5gCuS/1molCu = 191g CuS
2007-09-23 10:58:14 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
4.01g copper sulfide - 2.67g copper = a million.34g sulfur 2.67g Cu x [1mole/sixty 3.5g] = 0.0420 a million.34g S x [1mole/32g] = 0.0419 Divide each and each by using the smaller Cu: 0.0420 / 0.0419 = a million.00 S: 0.0419 / 0.0419 = a million. Empirical formula = CuS
2016-12-17 08:34:58 · answer #2 · answered by ? 4 · 0⤊ 0⤋