√20=√(4*5)=√4*√5=2√5
5=√5*√5
therefore √20/5 = 2/√5
the answer is 1/√5, as the first number is double the second.
2007-09-23 10:25:54
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answer #1
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answered by samuelll 2
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Is this (√20) / 5, or √ (20 / 5)?
In the first case:
√20 = √(4 x 5) = √4 x √5 = 2√5
Thus (√20) / 5 = (2√5) / 5.
1/√5 = (1 x √5) / (√5 x √5) = (√5) / 5.
So now we have (2√5) / 5 - (√5) / 5. That's simple to solve: The answer's (√5) / 5.
Then, finally, we can simplify (√5) / 5 back into 1/√5 by reversing what we did earlier.
2007-09-23 10:28:04
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answer #2
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answered by Anonymous
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= √20 / 5 - 1 / √5
= 2√5 / 5 - 1 / √5
= (2 / 5) √5 - √5 / 5
= (1 / 5) √5
2007-09-24 09:47:54
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answer #3
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answered by Como 7
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Sqrt(5)/5
2007-09-23 10:25:50
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answer #4
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answered by Bonhomme 1
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?20/5-a million/?5 is the concern. First we rationalize the denominator of a million/?5, so which you multiply a million/?5 with the aid of ?5/?5, which turns right into a million?5/5, so which you will now subtract with ?20/5 (?20-?5)/5 ?20 might properly be simplified to 2?5. once you subtract radicals, you subtract whats outdoors the unconventional, and only it the unconventional is comparable( ?2,?2). so the respond is ?5/5.
2016-11-06 04:50:38
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answer #5
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answered by Anonymous
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sqrt(20)/5 -1/sqrt(5)
=2*sqrt(5)/5-sqrt(5)/5
=sqrt(5)/5(2-1)
= sqrt(5)/5. ANS.
2007-09-23 10:37:53
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answer #6
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answered by Anonymous
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sqrt(20)/5 - 1/sqrt(5)
sqrt(20)/5 - (sqrt(5))/5
[sqrt(20) - sqrt(5)]/5 =
[2 sqrt(5) - sqrt(5)]/5 =
sqrt(5)[2-1]/5 =
sqrt(5)/5 =
(1/5) sqrt(5)
2007-09-23 10:35:26
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answer #7
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answered by mohanrao d 7
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rt(20)/5-1/rt5
rt(4)rt(5)/5-1/rt5
2rt(5)/5-1/rt5 Xrt5/rt5
2rt(5)/5 - rt(5)/5
{2rt(5) - 1rt(5)}/5
rt(5)/5 From here you could go to 2.236/5, = 0.447, but
I think they want the answer as rt(5) /5
2007-09-23 10:31:37
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answer #8
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answered by Grampedo 7
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1. =2
2. .blablablablabla its a big decimal it's irrational i know that...
2007-09-23 10:24:25
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answer #9
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answered by nick 2
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