If a car rolls gently (v0 = 0) off a vertical cliff, how long does it take it to reach 77 km/h?in seconds?

Question

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Answer 1

All items fall at the same speed when gravety takes a hold of them. Unless you teacher is adding wind resistance as well.

Answer 2

ah.. good question

here you treat this problem as a free fall, since projectiles launched at horizontal motions, fall at the same rate as an object dropped from rest.

since initial speed, or velocity is 0.. it can only be free fall

therefore

lets use our equation of velocity
as

vf=final velocity
v0= initial velocity
g=acc, of gravitiy
t=time

vf=v0 -gt
since velocity downward is negative, 77 km/hr = 21.3888 m/s

we set it as
-21.3888 m/s = 0 -9.81t
solving for t give

t= 2.18 seconds approximately.....

hope that helps.

Answer 3

I could answer the question but you dont have all pertinant information for a proper answer,I assume the question is of a humoris mature but the fact will never the less be just as critical to the answer.how high is the cliff?what is the gravational forces involved,Mars neptune pluto The moon?you dont specify so I dont think you have really thought the problem through,If you had you might be smart enough to answer it your self.Give it a try,Then push your car off the cliff to verefy the results.

Answer 4

gravity, thus the acceleration, is 9.8 m/s.
v(f) = v(i) + at
(final velocity = intitial velocity + acceleration*time)

77km/h = 21.388...m/s

21.388=0 + (9.8)t
21.388/9.8=t
t=2.18s

Answer 5

2.8 seconds.