solving for x?

0 ⤊

log[base2](3x+2) - log[base2](x-2) = 3

when i did the quotient law i got

log[base2](3x+2) / (x-2) = 3 ...............whats the next step?

2007-09-23 08:38:18 · 2 answers · asked by C.L. ~Raptors~ 4 in Science & Mathematics ➔ Mathematics

2 answers

yea thats right now eliminate the logbase

(3x+2)/(x-2) = 2^3

3x+2)/(x-2)=8

3x+2=8 x -16

5 x = 18

x= 18 / 5

2007-09-23 08:49:42 · answer #1 · answered by dragongml 3 · 0⤊ 0⤋

log [base 2] (3x+2)/(x-2) = 3, so

(3x+2)/(x-2) = 2 power 3, because the base goes right side

now (3x+2)/(x-2) = 8 => 3x+2 = 8(x-2) => 3x+2 = 8x-16

so 8x-3x = 2+16 => 5x = 18=> x = 18/5

2007-09-23 15:52:58 · answer #2 · answered by Metallurgist 2 · 0⤊ 0⤋