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You can think of the work-kinetic energy theorem as a second theory of motion, parallel to Newton's laws in describing how outside influences affect the motion of an object. In this problem work out parts (a) and (b) separately from parts (c) and (d) to compare the predictions of the two theories. In a rifle barrel, a 15.0 g bullet is accelerated from rest to a speed of 740 m/s. (a) Find the work that is done on the bullet in kJ. (b) If the rifle barrel is 70.0 cm long, find the magnitude of the average total force that acted on it, as F = W / (r cos ) in kN. (c) Find the constant acceleration of a bullet that starts from rest and gains a speed of 740 m/s over a distance of 70.0 cm in km/s^2. (d) If the bullet has mass 15.0 g, find the total force that acted on it as F = ma in kN.

2007-09-23 07:16:22 · 1 answers · asked by green 1 in Science & Mathematics Physics

1 answers

(a) The work was done to increase the kinetic energy of the bullet:
W = 0.5*m*v^2 = 0.5*0.015*740^2 = 4.11 (kJ)
(b) L = 0.7m
F = W / L = 4.11 (kJ)/0.7m = 5.87(kN)
(c) (740 m/s)^2 = 2*a*0.7m
a = (740 m/s)^2 /1.4m = 3.91 km/s^2
(d) F = ma = 0.015kg*3.91 km/s^2 = 5.87(kN)

2007-09-24 17:12:44 · answer #1 · answered by Hahaha 7 · 0 0

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