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Differentiate.

z = w^(3/2)(w + ce^w)
z'(w)= ?

w is the variable

2007-09-23 06:59:54 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

z'(w) = (3/2) w^{1/2} (w+ce^w)+w^{3/2}(1+ce^w)

2007-09-27 06:13:41 · answer #1 · answered by robert 6 · 0 0

z´= 3/2w^1/2(w+ce^w)+w^3/2(1+ce^w)

2007-09-23 07:04:18 · answer #2 · answered by santmann2002 7 · 0 0

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