If you can revolve an object on a string 0.7m long, at a rate of 9revolutions/second. How can you find the speed at which the object is going? Or the centripetal acceleration?
2007-09-23 04:56:14 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
omega = 2 pi f
v = r omega
v = 2 pi r f
centripetal acceleration is given by:
a = omega^2 r = (2 pi f)^2 r
They give you f and r. Plugnchug.
2007-09-23 05:03:14 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The speed part is easy.
In one revolution, the object travels one circumference of the circle. That equals 2Ï•(0.7m).
So, if it travels 9 revs/sec, its speed is:
9(2Ï•(0.7m)) / sec
> the centripetal acceleration?
One formula for centripetal acceleration is:
a = v²/r
v is the velocity that we just calculated.
r is the radius of the circle (0.7 m)
2007-09-23 12:02:55 · answer #2 · answered by RickB 7 · 0⤊ 0⤋