Projectile motion?

Question

In 1978, Geoff Capes of Great Britain threw a heavy brick a horizontal distance of 44.5m. Find the velocity of the brick at the highest point of its flight.

Can someone show me the steps to answering this? please.

Answer 1

A Projectile travels in the horizontal as well as vertical directions and traces a curvilinear path.

If the brick is projected with initial velocity Vo inclined at an angle a with the horizontal.

The motion of the brick can be studied by resolving this initial velocity in horizontal and the vertical directions.

Vx= Vo cos a (Horizontal component)

Here horizontal component of the velocity produces motion in horizontal direction which is constant as no acceleration.

Vy= Vo sin a (Vertical component)

Here vertical component of the velocity produces motion in vertical direction which is under effect of gravitational acceleration and goes on decreasing as the object(here brick) goes up. When it achieves maximum height the vertical component of velocity decreases to zero, so it can not go up and starts coming down.

So at the highest point of flight, velocity of brick is only Vo cos a.

If considering this range as maximum horizontal range,as it might be highest achieved range, angle of projection is 45 degrees. Now in following formula for Horizontal Range,

R= (Vo^2 sin 2a)/g

If a= 45, sin 2*45= sin 90 = 1.

So formula reduces to R= Vo^2/g

R=44.5 m, g= 9.81 m/sec^2,

Vo= 20.89 m/sec

Therefore at highest point
Vx= Vo cos a
Vx= 20.89 * cos 45
= 14.771 m/sec

Answer 2

The path of the brick is a parabola.The extremities are 44.50 metres apart. The height and velocity could be worked out only after the force and mass are known

Answer 3

You can't do this without knowing the elevation angle.

If you assume the ideal angle (45 degrees), you can get range:
r = v^2 sin (2 elevation) / g = v^2 / g

so v = sqrt (gr)

The horizontal velocity is given by:
vx = v cos theta = sqrt (gr/2)

vx never changes, and at the peak, vy is zero, so that's your answer right there. They give you r. You know g. Plugnchug.

Answer 4

The destructive sign refers back to the direction of the tension, it quite is downward. with the aid of convention, destructive speed and destructive acceleration are downward. in case you placed g as helpful, then a projectile released upwards might have destructive speed, which does not make intuitive experience.

Answer 5

You don´t need the mass but you need more information

Answer 6

plz dont post wrong questions