In this equation
-x+y(cubed) = 12
2007-09-23 03:05:55 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Yes. You can solve:
y = cuberoot( 12 + x )
This is a function. Y is a function of X. The important thing to remember is that cube roots are unique, for real numbers. Unlike square roots, which would give you a ±, leading to Y not being a function of X.
2007-09-23 03:13:32 · answer #1 · answered by сhееsеr1 7 · 0⤊ 0⤋
uhmm.. exactly what are you looking for here? this is simply a cubic equation equivalent to y(cubed) = 12+x. you can plug in *any* x value and simply compute the corresponding y value
2007-09-23 10:11:00 · answer #2 · answered by january 2 · 0⤊ 1⤋
Y takes on different values depending on the different values of x. x is an independent variable and y is the dependent variable.
2007-09-23 10:09:59 · answer #3 · answered by Swamy 7 · 0⤊ 1⤋
ummmm....not really, 12 equals that equation, X and Y are two very different things, two diff variables.
2007-09-23 10:15:46 · answer #4 · answered by Yours Truly 3 · 0⤊ 1⤋
depending on what is considered a value of y,y is indepentent of x therefor not being a value of x.
2007-09-23 10:33:12 · answer #5 · answered by scide i 2 · 0⤊ 1⤋
nope.It will not be the value of x .
2007-09-23 10:14:14 · answer #6 · answered by varsha_shinde66 1 · 0⤊ 1⤋