A tourist travelled 3/8 of a certain journey by train, 3/5 of it by bus and the rest by taxi. If the total distance travelled was 320km, how far did the tourist travel by taxi?
2007-09-23 02:35:17 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Part of jouney undertaken by taxi
=1-(3/8+3/5)
=40/40 -15/40-24/40
=1/40
Therefore distance travelled by taxi
=1/40 of 320 km
=1/40*320
=8 km
2007-09-23 02:42:30 · answer #1 · answered by alpha 7 · 1⤊ 0⤋
3/8 + 3/5 =
15/40 + 24/40 + 39/40 is how much he traveled.
39/40 x 320/1 = 12480/40 or 312/1 or 312km.
he traveled 312km. 320 - 312 = 8km.
the tourist traveled 8km by taxi
2007-09-23 09:47:35 · answer #2 · answered by delux 2 · 0⤊ 1⤋
3/8 of 320 km = 120 km
3/5 of 320 km = 192
So, distance travelled by taxi = 320 - (120 + 192) = 320 - 312 = 8 km
He travelled 8 km by taxi.
2007-09-23 09:41:06 · answer #3 · answered by Swamy 7 · 1⤊ 0⤋
3/8= 15/40
3/5=24/40
15/40 +24/40 = 39/40
which means he traveled 39/40 by both train and bus, and remaining 1/40 was traveled by taxi
then multiply 1/40 x320
2007-09-23 09:43:06 · answer #4 · answered by sexy joker 6 · 0⤊ 1⤋
Three
2007-09-23 11:51:57 · answer #5 · answered by Anonymous · 0⤊ 0⤋