math problem help...I couldn't figure out this one?

Question

there are 27 members in a swimming club. 19 have brown hair. 14 have blue eyes.. 11 have both...

how many have blue eyes?


can you show me how you got the answer?

Answer 1

There is some error in problem definition. How many have blue eyes? 14 as given in the problem. But how many have blue eyes but no brown hair? 14 - 11 = 3

How many don't have blue eyes? 27 - 14 = 13

The above are the possible numbers that could be derived from the given facts.

Answer 2

I am not sure whether you want to know how many people have blue eyes or how many people have only blue eyes (not brown hair). In the first case it is 14. But for the second case it is the following:
19 have brown hair, 14 have blue eyes.
11 of the people who have blue eyes also have brown hair.This leaves us with 14-11= 3.
therefore 3 people have only blue eyes.

Answer 3

'there are 27 members in a swimming club. 19 have brown hair. 14 HAVE BLUE EYES.. 11 have both...'

Voila

Answer 4

total member=27

blue eyes only = 14-11= 3

brown hair only= 19-11=8

neither blue eyes nor brown hair=27-3-8-11=5


And the answer is none of them have blue eyes, because their eyes all have turned red due contact with the water. hehehe...

Answer 5

20 have blue eyes. 19 + 14 = 33

33 exceeds 27.

33 - 27 = 6

(11 have both is not necessary)

14 + 6 = 20

Answer 6

I think perhaps you typed the question wrong? You ask how many have blue eyes, but you state in the problem that 14 have blue eyes, so either you aren't reading carefully, or you misstated the problem.

Answer 7

14 have blue eyes, it's stated in the question.

Answer 8

14 have blue eyes, the question tells ya