2007-09-23 02:12:29 · 3 answers · asked by WR 1 in Science & Mathematics ➔ Mathematics
there's not one
cos is constantly moving between -1 and 1, and it doesn't tend toward any number as x approaches infinity
2007-09-23 02:16:10 · answer #1 · answered by ccw 4 · 2⤊ 1⤋
Since the cosine oscillates with period 2.pi it is not possible to assign a definite value at infinity.
However for special purposes of analysis(where other 'drastic' considerations are made) the value for,
cos (infinity) = sin (infinity) = 0 is used.
2007-09-23 02:47:37 · answer #2 · answered by yasiru89 6 · 0⤊ 0⤋
It is undefined.
For instance:
cos (2n*pi) = 1 for every integer n.
Thus lim(n->inf)cos(2n*pi) = 1
cos (pi/2 + n*pi) = 0 for every integer n
Thus, lim(n->inf) cos(pi/2 + n*pi) = 0
2007-09-23 02:30:41 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋