I think it is m^-3 x m^3??
If so I think they cancel each other out
however if this is right would my final answer be m or 0?
2007-09-22 21:58:24 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Other - Science
m^3 * m * m^2 = m^(3+1+2) = m^6
m^-3 * m^3 = m^(-3+3) = m^0 = 1.
Anything ^0 is one.
When you multiply a bunch of things with exponents, and they all have the same base, you add the exponents together.
2007-09-22 22:06:41 · answer #1 · answered by lomelinde 3 · 1⤊ 0⤋
M^3*m^2*m=m^(3+2+1)=m^6
if you meant somehting like m^(-3)*m*m^2 than the answer is m^0=1.
all number to the power of 0 are equal to 1.
2007-09-23 05:06:59 · answer #2 · answered by unonimy 2 · 0⤊ 0⤋
When multiplying numbers with the same base, simply add the powers together and that is the resulting exponenet.
3 + 1 + 2 = 6
Your final answer is m^6.
2007-09-23 05:08:54 · answer #3 · answered by lhvinny 7 · 1⤊ 0⤋
m2>6?
2007-09-23 05:05:29 · answer #4 · answered by bruvvamoff 5 · 0⤊ 0⤋