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A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hour of labor to produce, and the wreaths take 2 hours. The labor available is limited to 80 hours per week, and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths

2007-09-22 16:19:57 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

x=no. of bouquets
y=no. of wreaths

1x +2y < or = 80
x + y < or = 60

2007-09-22 16:28:33 · answer #1 · answered by Grampedo 7 · 0 0

You should make a sketch of this to figure out the inequalities. If x is hours and y is products, we have starting at 0,0 and going clockwise from
Point A= 80,0 (labor constraint)
The origin
Point B=0,60 (product constaint)
Point C= 60,60 (max production of boquets)
The line y=120-x, which passes through point C
(trade-off between boquets and wreaths)
Point D=80,40 (max production of wreaths)
The line x=80
(never mind, I didn't read the problem. Just ignore me and look at the other answers)

2007-09-22 23:45:49 · answer #2 · answered by cattbarf 7 · 0 0

x=bouquets , y = wreaths
[hours] x + 2y <80
[items] x + y < 60

2007-09-22 23:30:42 · answer #3 · answered by Brian D 5 · 0 0

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