Avogadro's number of aluminum(Al)atoms would weigh?

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Avogadro's number of aluminum(Al)atoms would weigh?

2007-09-22 15:35:58 · 2 answers · asked by soul2true 1 in Science & Mathematics ➔ Chemistry

2 answers

The mass of 6.02214X10^23 (Avogadro's number) of Al atoms would be 26.9815 g. Avogadro's number is the number of things in a mole of things. An element's atomic weight is the mass of one mole of the element. So Avogadro's number of hydrogen atoms weighs 1.00794 g, Avogadro's number of carbon atoms weighs 12.01115 g, Avogadro's number of oxygen atoms weighs 15.9994 g, Avogadro's number of silicon atoms weighs 28.0855 g, and so on.

2007-09-22 15:49:56 · answer #1 · answered by Bill2006 2 · 0⤊ 0⤋

It would weigh 27 grams, since that number holds one mole. The weight of 1 mole of Al is 27 gms so that is easy to figure.

2007-09-22 15:39:33 · answer #2 · answered by Rich Z 7 · 2⤊ 0⤋